You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad version are also bad.

Suppose you have n versions [1, 2, ..., n] and you want to find out the first bad one, which causes all the following ones to be bad.

You are given an API bool isBadVersion(version) which will return whether version is bad. Implement a function to find the first bad version. You should minimize the number of calls to the API.

找出第一个出错的版本，题目要求尽可能少的调用给定的函数，所以使用二分搜索。找出第一个出错的值即可。

// Forward declaration of isBadVersion API.bool isBadVersion(int version);class Solution {public:    int firstBadVersion(int n) {        int left = 1, right = n;        while (left < right) {            int mid = left + (right - left) / 2;            if (isBadVersion(mid))                right = mid;            else                left = mid + 1;        }        return right;    }};// 0 ms